The area of sign is 45 in^2
Further explanation:
Let W be the width
and
L be the length
The according to given statements
[tex]2L+2Y=36\\L=5W[/tex]
Putting L=5W in first equation
[tex]2(5W)+2W=36\\10W+2W=36\\12W=36\\W=\frac{36}{12}\\W=3\ inches\\Putting\ W=3\ in\ second\ equation\\L=5W\\L=5(3)\\L=15\ inches\\Now,\\Area=L*W\\= 15*3\\=45\ in^2[/tex]
The area of sign is 45 in^2
Keywords: Area of rectangle, Perimeter of rectangle
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