Question

(Algebra 2) write a polynomial function of least degree with integral coefficients that has the given zeros.
Please show the steps and explain!!

Answer 1

Answer:

$x^{2} -2ix+3=0$ .

Step-by-step explanation:

Given the zeroes of the polynomial are

a=-i . and b=3i

The recquired polynomial is $(x-a)(x-b)=0$

On substituting the values of a and b we get

$(x+i)(x-3i)=0$

$x^{2} -3xi+ix-3i^{2}=0$

$x^{2} -2ix+3=0$ .       (∵$i^{2}=-1$)