Respuesta :

Answer:

[tex]x^{2} -2ix+3=0[/tex] .

Step-by-step explanation:

Given the zeroes of the polynomial are

a=-i . and b=3i

The recquired polynomial is [tex](x-a)(x-b)=0[/tex]

On substituting the values of a and b we get

[tex](x+i)(x-3i)=0[/tex]

[tex]x^{2} -3xi+ix-3i^{2}=0[/tex]

[tex]x^{2} -2ix+3=0[/tex] .       (∵[tex]i^{2}=-1[/tex])

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