Respuesta :
Answer:
The x-intercept is 2.
The function has no y-intercept.
The vertical asymptote of the function is x=0.
The horizontal asymptote of the function is x=0.
The function has hole at x=4.
Step-by-step explanation:
The given function is
[tex]f\left(x\right)=\dfrac{(3x-6)(x-4)}{x(x-4)}[/tex]
Cancel out common factors.
[tex]f\left(x\right)=\dfrac{3x-6}{x}[/tex]
(i) x-intercept.
Substitute f(x)=0, in the given function.
[tex]0=\dfrac{3x-6}{x}[/tex]
[tex]0=3x-6[/tex]
[tex]-3x=-6[/tex]
[tex]x=2[/tex]
The x-intercept is 2.
(i) y-intercept.
Substitute x=0, in the given function.
[tex]f\left(x\right)=\dfrac{3(0)-6}{(0)}=\infty[/tex]
The function has no y-intercept.
(iii) Vertical asymptote.
Equate the denominator equal to 0.
[tex]x=0[/tex]
Therefore, the vertical asymptote of the function is x=0.
(iv) Horizontal asymptote.
If degree of numerator and denominator are same, then horizontal asymptote is
[tex]y=\frac{\text{Leading coefficient of numerator}}{\text{Leading coefficient of denominator}}[/tex]
[tex]y=\frac{3}{1}[/tex]
[tex]y=3[/tex]
Therefore, the horizontal asymptote of the function is x=0.
(v) End behavior
[tex]f(x)\rightarrow 3\text{ as }x\rightarrow -\infty[/tex]
[tex]f(x)\rightarrow \infty\text{ as }\rightarrow 0^{-}[/tex]
[tex]f(x)\rightarrow -\infty\text{ as }\rightarrow 0^{+}[/tex]
[tex]f(x)\rightarrow 3\text{ as }\rightarrow \infty [/tex]
(vi) holes
Equate the cancel factors equal to 0, to find the holes.
[tex]x-4=0[/tex]
[tex]x=4[/tex]
The function has hole at x=4.
