Answer:
Average speed, V = 37.5 Km/h
Acceleration, a = 8035.71 Km/h²
Distance traveled, d = 210 m
Explanation:
Given that,
The initial speed of the bus, u = 15 Km/h
The final speed of the bus, v = 60 Km/h
The time period of the bus is, t = 20 s
= 0.0056 h
The average speed of the bus
V = (15 + 60) / 2
= 37.5 m/s
The average speed = 37.5 m/s
The acceleration of the bus
a = (v - u) / t
= (60 - 15) / 0.005
= 8035.71 Km/h²
The acceleration is = 8035.71 Km/h²
The distance traveled by bus,
d = v x t
= 8035.17 x 0.005
= 0.21 Km or 210 m
The distance traveled = 210 m
