Answer: -1.7
Step-by-step explanation:
Given : Another home business has an average income of $1.200.00 per month with a standard deviation of $100.00.
i.e.[tex]\mu=\$1200.0[/tex]
[tex]\sigma=\$100.00[/tex]
Let x represents the monthly income.
Since . [tex]z=\dfrac{x-\mu}{\sigma}[/tex]
For x= 1030 , we have
[tex]z=\dfrac{1030-1200}{100}=-1.7[/tex]
Hence, the required z-score = -1.7