Respuesta :
Answer:
Simplified form of fifth root of x times the fifth root of x times the fifth root of x times the fifth root of x is [tex]\sqrt[5]{x^{4}}[/tex]
Solution:
Need to find simplified form of fifth root of x times the fifth root of x times the fifth root of x times the fifth root of x. That is need to find simplified form of following expression.
[tex]\sqrt[5]{x} \times \sqrt[5]{x} \times \sqrt[5]{x} \times \sqrt[5]{x}[/tex]
[tex]\text { since } \sqrt[n]{a}=(a)^{\frac{1}{n}}[/tex] we get
[tex]=>(x)^{\frac{1}{5}} \times(x)^{\frac{1}{5}} \times(x)^{\frac{1}{5}} \times(x)^{\frac{1}{5}}[/tex]
Now using law of exponent that is [tex]\mathrm{a}^{\mathrm{m}} \times \mathrm{a}^{\mathrm{n}}=\mathrm{a}^{\mathrm{m}+\mathrm{n}}[/tex]
[tex]\begin{array}{l}{\Rightarrow(x)^{\frac{1}{5}} \times(x)^{\frac{1}{5}} \times(x)^{\frac{1}{5}} \times(x)^{\frac{1}{5}}} \\\\ {=(x)^{\frac{1}{5}+\frac{1}{5}} \times(x)^{\frac{1}{5}}} \\\\ {=(x)^{\frac{2}{5}} \times(x)^{\frac{2}{5}}} \\\\ {=(x)^{\frac{2}{5}} \times(x)^{\frac{2}{5}}} \\\\ {=(x)^{\frac{2}{5} +\frac{2}{5} \\\\ {=(x)^{\frac{4}{5}}}\end{array}[/tex]
Using another law of exponent that is [tex](a)^{m \times n}=\left((a)^{m}\right)^{n}[/tex] we get
[tex]\begin{array}{l}{(x)^{\frac{4}{5}}=(x)^{4 \times \frac{1}{5}}=\left((x)^{4}\right)^{\frac{1}{5}}} \\\\ {\left((x)^{4}\right)^{\frac{1}{5}}=\sqrt[5]{x^{4}}}\end{array}[/tex]
Hence the simplified form of fifth root of x times the fifth root of x times the fifth root of x times the fifth root of x is [tex]\sqrt[5]{x^{4}}[/tex]