For this case we have a function of the form[tex]y = f (x)[/tex] where:
[tex]f (x) = \frac {x ^ 4} {x ^ 3}[/tex]
We simplify eliminating common terms of the numerator and denominator:
[tex]f (x) = x[/tex]
We must find the values of the function when:
x = {-2, 0, 3, 5, 7}
So, we have:
For [tex]x = -2[/tex]:
[tex]f (-2) = - 2[/tex]
For [tex]x = 0[/tex]
[tex]f (0) = 0[/tex]
For [tex]x = 3[/tex]
[tex]f (3) = 3[/tex]
For [tex]x = 5[/tex]
[tex]f (5) = 5[/tex]
For [tex]x = 7[/tex]:
[tex]f (7) = 7[/tex]
Thus, the values of the function are:
y = {-2, 0, 3, 5, 7}
Answer:
y = {-2, 0, 3, 5, 7}