Question

what is y=x^4/x^3 when values of x= {-2, 0, 3, 5, 7}

Answer 1

For this case we have a function of the form$y = f (x)$ where:

$f (x) = \frac {x ^ 4} {x ^ 3}$

We simplify eliminating common terms of the numerator and denominator:

$f (x) = x$

We must find the values of the function when:

x = {-2, 0, 3, 5, 7}

So, we have:

For $x = -2$:

$f (-2) = - 2$

For $x = 0$

$f (0) = 0$

For $x = 3$

$f (3) = 3$

For $x = 5$

$f (5) = 5$

For $x = 7$:

$f (7) = 7$

Thus, the values of the function are:

y = {-2, 0, 3, 5, 7}

Answer:

y = {-2, 0, 3, 5, 7}