Respuesta :

For this case we have a function of the form[tex]y = f (x)[/tex] where:

[tex]f (x) = \frac {x ^ 4} {x ^ 3}[/tex]

We simplify eliminating common terms of the numerator and denominator:

[tex]f (x) = x[/tex]

We must find the values of the function when:

x = {-2, 0, 3, 5, 7}

So, we have:

For [tex]x = -2[/tex]:

[tex]f (-2) = - 2[/tex]

For [tex]x = 0[/tex]

[tex]f (0) = 0[/tex]

For [tex]x = 3[/tex]

[tex]f (3) = 3[/tex]

For [tex]x = 5[/tex]

[tex]f (5) = 5[/tex]

For [tex]x = 7[/tex]:

[tex]f (7) = 7[/tex]

Thus, the values of the function are:

y = {-2, 0, 3, 5, 7}

Answer:

y = {-2, 0, 3, 5, 7}

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