Question

Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).

y = 2x + 6

y = - x + 3

y = - x + 6

y = 2x + 3

Answer 1

The equation of line is:

$y=-\frac{1}{2}x+6$

Further explanation:

Given

y = 2x + 2

Comparing it with standard form:

y=mx+b

Let m1 be the slope of given line

$m_1=2$

We know that product of slopes of two perpendicular lines is -1

Let m2 be the slope of second line

$m_1.m_2=-1\\2*m_2= -1\\m_2 = -\frac{1}{2}$

Putting the value of m2 in standard form

$y=-\frac{1}{2}x+b$

To find the value of b, putting (6,3) in equation

$3=-\frac{1}{2}(6)+b\\3=-3+b\\3+3=b\\b=6$

Putting the values of b and m, we get

$y=-\frac{1}{2}x+6$

The equation of line is:

$y=-\frac{1}{2}x+6$

Keywords: Slope, Point-slope form

Learn more about slope at:

• brainly.com/question/2688526
• brainly.com/question/2920401

#learnwithBrainly

Answer 2

Answer:

its actually c

Step-by-step explanation: