Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).

y = 2x + 6

y = - x + 3

y = - x + 6

y = 2x + 3

Respuesta :

The equation of line is:

[tex]y=-\frac{1}{2}x+6[/tex]

Further explanation:

Given

y = 2x + 2

Comparing it with standard form:

y=mx+b

Let m1 be the slope of given line

[tex]m_1=2[/tex]

We know that product of slopes of two perpendicular lines is -1

Let m2 be the slope of second line

[tex]m_1.m_2=-1\\2*m_2= -1\\m_2 = -\frac{1}{2}[/tex]

Putting the value of m2 in standard form

[tex]y=-\frac{1}{2}x+b[/tex]

To find the value of b, putting (6,3) in equation

[tex]3=-\frac{1}{2}(6)+b\\3=-3+b\\3+3=b\\b=6[/tex]

Putting the values of b and m, we get

[tex]y=-\frac{1}{2}x+6[/tex]

The equation of line is:

[tex]y=-\frac{1}{2}x+6[/tex]

Keywords: Slope, Point-slope form

Learn more about slope at:

  • brainly.com/question/2688526
  • brainly.com/question/2920401

#learnwithBrainly

Answer:

its actually c

Step-by-step explanation:

ACCESS MORE
EDU ACCESS