Question

Arrange the bonds between H, O, and F from most polar to least polar based on electronegativity.
Bonds to order:
O-F
H-F
H-O
H-H

Answer 1

Answer:

H-F> H-O> O-F

while H-H is nonpolar.

Explanation:

The bond is polar when electronegativity difference of both bonded atom is greater than 0.4.

Electronegativity values of O. F and H are

O = 3.4

H = 2.2

F = 3.98

For O-F

3.98 - 3.4 = 0.58

For H-F

3.98 - 2.2 = 1.78

For H-O

3.4 - 2.2 =  1.2

For H-H

2.2 -2.2 = 0

So H-H is nonpolar.

Answer 2

The bond order from the most polar to the least polar based on their electronegativity is H-F > H-O > O-F

However, H-H is non polar

What is electronegativity?

Electronegativity can simply be defined as that property of an atom of an element to attract shared electrons when forming a chemical bond.

Generally, this property of an atom increases with its tendency to attract the electrons of a bond

So therefore, the bond order from the most polar to the least polar based on their electronegativity is given below:

H-F > H-O > O-F

Learn more about electronegativity:

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