Question

if (a^3+27)=(a+3)(a^2+ma+9) then m equals

Answer 1

Answer:

m = - 3

Step-by-step explanation:

a³ + 27 ← is a sum of cubes and factors in general as

a³ + b³ = (a + b)(a² - ab + b²), thus

a³ + 27

= a³ + 3³

= (a + 3)(a² - 3a + 9)

comparing a² - 3a + 9 to a² + ma + 9, then

m = - 3

Answer 2

If the expression (a³+27)=(a+3)(a²+ma+9), then the value of m is; m = -3.

From the question; (a^3+27)=(a+3)(a^2+ma+9).

To fund the value of m; we must first expand the right hand side of the equation so that we have;

• a³ + 27 = a³ + ma² + 9a + 3a² + 3ma +27

By collecting like terms, we are left with the expression;

• ma² + 3a² + ma + 9a = 0

By dividing through by a, we have;

• ma + 3a + m + 9 = 0.

By collecting like terms, we have;

• m(a+1) = -3(a+1)

And, finally by dividing both sides of the equation by (a+1);. we have;

m = -3.

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