One summer you charge $20 to mow a lawn and $10 to trim bushes. You want to make $300 in one week. An algebraic model for your earnings is 20x + 10y=300,where x is the number of lawns you mow and y is the number of bushes you trim. Solve for the equation for y.

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Answer

given,

charge to mow a lawn = $20

charge to trim bushes = $10

money made in one week = $ 300

algebraic model

20 x + 10 y = 300

writing equation for y

10 y = 300 - 20 x

dividing both side by '10'

[tex]\dfrac{10}{10}y = \dfrac{300}{10} - \dfrac{20}{10} x[/tex]

[tex]y = 30 - 2 x[/tex]

x(no. of mowed )        y (no. of bushes)

      0                           30

       5                           20

       10                         10

       15                          0

Answer:

x = 10

y =5

Step-by-step explanation:

Let x be the number of lawns you mow and y is the number of bushes you trim

Amount charged is $20 to mow a lawn and $10 to trim bushes.

To make $300 in one week,

20x + 10y=300---------1

From the question, the amount you charge to now a lawn = twice the amount charged to trim bushes

x = 2y

Put x = 2y in eqn 1

20(2y)+10y = 300

50y = 300

y = 300/60/= 5 bushes

x = 2y = 2×5

= 10 lawns

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