57.14 % oxygen
Explanation:
To calculate the percent composition of a particular element in a substance we use the following algorithm. First we need to know the molecular mass of the substance.
molecular mass of carbon monoxide = 28 g/mole
Then devise the following reasoning considering 1 mole of carbon monoxide:
if in 28 grams of carbon monoxide we have 16 grams of oxygen
then in 100 grams of carbon monoxide we have X grams of oxygen
X = (100 × 16) / 28 = 57.14 % oxygen
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