Question

Simplify the expression
x2 − 5x + 6 / x − 3
to lowest terms, and identify the value(s) of x that must be excluded to avoid
division by zero.

Answer 1

Answer:

$\frac{x^3-7x^2+15x+6}{x-3}$

Step-by-step explanation:

$x^2-5x+\frac{6}{x-3}$

applying the minimum common multiple for each term

minimum common multiple: common and not common with its greatest exponent.

It is divided by the denominator and multiplied by the numerator

$\frac{(x^2.(x-3))-(5x.(x-3))+6}{x-3}$

apply distributive property

$\frac{x^3-3x^2-5x^2+15x+6}{x-3}$

group similar terms

$\frac{x^3-7x^2+15x+6}{x-3}$