Answer:
[tex]\textbf{The equation of the circle is: $ {(x-4)}^2 + {(y-5)}^2 = 9 $.}\\[/tex]
Step-by-step explanation:
[tex]\textup{The equation of a circle is given by:}\\$c = \sqrt{{(x-h)}^2 + {(y-k)}^2} = r^2$\\\textit{where $(h,k)$ represents the centre of the circle and $r$ the radius.}\\\textup{Given the centre of the circle is $(4,5)$ and radius is $3$.}\\$ \therefore $ We have $c = \sqrt{{(x-4)}^2 + {(y-5)}^2} = 3^2$$\implies {(x-4)}^2 + {(y-5)}^2 = 9$[/tex]