Solve and show work please
(2x^2-4xy+2y^2)(3x-4)

Answer:
Step-by-step explanation: Distribute sum groups.
2{x}^{2}(3x-4)-4xy(3x-4)+2{y}^{2}(3x-4)2x
2
(3x−4)−4xy(3x−4)+2y
2
(3x−4)
Expand.
6{x}^{3}-8{x}^{2}-4xy(3x-4)+2{y}^{2}(3x-4)6x
3
−8x
2
−4xy(3x−4)+2y
2
(3x−4)
Expand.
6{x}^{3}-8{x}^{2}-(12{x}^{2}y-16xy)+2{y}^{2}(3x-4)6x
3
−8x
2
−(12x
2
y−16xy)+2y
2
(3x−4)
Expand.
6{x}^{3}-8{x}^{2}-(12{x}^{2}y-16xy)+6{y}^{2}x-8{y}^{2}6x
3
−8x
2
−(12x
2
y−16xy)+6y
2
x−8y
2
Remove parentheses.
6{x}^{3}-8{x}^{2}-12{x}^{2}y+16xy+6{y}^{2}x-8{y}^{2}6x
3
−8x
2
−12x
2
y+16xy+6y
2
x−8y
2
Hope this helps!