Answer:
[tex](x-h)^{2} + (y-k)^{2} = r^{2}[/tex] is the equation of the circle.
Step-by-step explanation:
The general equation of the circle with center (h,k) and radius r is given as:
[tex](x-h)^{2} + (y-k)^{2} = r^{2}[/tex]
1) center (1,-4), radius: 3
Equation of the circle is: [tex](x-1)^{2} + (y+4)^{2} = 3^{2}[/tex]
2) center (0,2), diameter= 10 , so radius = d/2 = 5
Equation of the circle is: [tex](x-0)^{2} + (y-2)^{2} = 5^{2}[/tex]
3) center (-2,5), radius = 5
Equation of the circle is: [tex](x+2)^{2} + (y-5)^{2} = 5^{2}[/tex]
4) center (a, b), radies : 2
Equation of the circle is: [tex](x-a)^{2} + (y-b)^{2} = 2^{2}[/tex]