Question

circle q is centered at the origin with radius r point p(xy)lies on circle q make conjecture how can you find an equation relationg to the radius to the coordinates of point p brainly

Answer 1

Answer:

[tex]x^{2} +y^{2}=r^{2}[/tex]

Step-by-step explanation:

We know that the center-radius form of the circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being "r".

As given the center of circle q is origin ie,(0,0);

$h=0  and k=0$

Now substitute the point P in the equation of the circle as it lies on it.

$(x-0)^{2}+(y-0)^{2}=r^{2}$

$x^{2}+y^{2}=r^{2}$

Answer 2

Answer:

Because ΔPQS is a right triangle, apply the Pythagorean theorem.

x² + y² = r²

Step-by-step explanation:

just got it right edg 2021