Four milliliters of ink A is added to 10 milliliters of ink B, forming a mixture of inks. Ink A contains 10% blue pigment. Ink B contains an unknown percentage of blue pigment. The mixture of the two inks contains 35% blue pigment.
We will assume that B contains higher percentage of blue pigment than the mixture ( because A contains lower). First we will subtract: 35-10=15 and then: x-35 So we will make the proportion: 4 : 10 = (x-35) : 15 4 * 15 = 10(x-35) 60=10 x- 350 10 x =410 x = 41% Answer: Ink B contains 41 % of blue pigment.
