Question

a quadratic function in standard form with zeros -2/3 and -6

Answer 1

Answer:

x^2 + (20/3)x + 4

Step-by-step explanation:

we want f(x) = (x+6)(x+2/3)

=x^2 + (2/3)x + 6x + 12/3

= x^2 + (2/3)x + (18/3)x +4

= x^2 +(20/3)x +4