Question

Draw a fbd for a block at rest on a incline

Draw a fbd for a block at rest with a incline

Answer 1

Answer:

Find the diagram in attachment

Explanation:

In this problem we have a block at rest on the incline. There are only three forces acting on the block:

- The weight of the block, labelled as (mg), acting downward (where m = mass of the block and g = acceleration of gravity)

- The normal reaction exerted by the incline on the block, R, directed perpendicular to the plane

- The frictional force, $F_f$, acting up along the plane

It is possible to resolve the forces along the two directions - parallel and perpendicular to the plane. We find the following equations of motion:

- Parallel direction: $mg sin \theta - F_f = 0$

- Perpendicular direction: $R - mg cos \theta = 0$

where $\theta$ is the angle of the inclined plane.