Which equations represent the data in the table? Check all that apply.
y – 6 = y minus 6 equals StartFraction negative 5 Over 4 EndFraction left-parenthesis x plus 2 right-parenthesis.(x + 2)
y – 2 = –y minus 2 equals negative StartFraction 5 Over 4 EndFraction left-parenthesis x minus 1 right-parenthesis.(x – 1)
y + 2 = y plus 2 equals StartFraction negative 5 Over 4 EndFraction left-parenthesis x minus 6 right-parenthesis.(x – 6)
y – 1 = –y minus 1 equals negative StartFraction 5 Over 4 EndFraction left-parenthesis x minus 2 right-parenthesis.(x – 2)
y – 3.5 = –1.25x

Respuesta :

Answer:

a,d,e

Step-by-step explanation:

The equations that represent the table are

  • (a) [tex]y - 6 = -\frac 54(x + 2)[/tex]
  • (d) [tex]y -1 = -\frac 54(x -2)[/tex]
  • (e) [tex]y -3.5=-1.25x[/tex]

What are linear equations?

Linear equations are equations that have constant rates or slopes

From the complete question. the equation of the table is given as:

[tex]y - 6 = -\frac 54(x + 2)[/tex]

Add 5 to both sides of the equation

[tex]y - 6 + 5 = -\frac 54(x + 2) + 5[/tex]

[tex]y -1 = -\frac 54(x + 2) + 5[/tex]

Expand the bracket

[tex]y -1 = -\frac 54x -\frac 52 + 5[/tex]

Take LCM

[tex]y -1 = -\frac 54x +\frac {-5 + 10}2[/tex]

[tex]y -1 = -\frac 54x -\frac {5}2[/tex]

Factorize

[tex]y -1 = -\frac 54(x -2)[/tex]

Also, we have:

[tex]y - 6 = -\frac 54(x + 2)[/tex]

Open brackets

[tex]y -6 = -\frac 54x -\frac 52[/tex]

Express fractions as decimals

[tex]y -6 =-1.25x -2.5[/tex]

Add 2.5 to both sides

[tex]y -3.5=-1.25x[/tex]

Hence, the equations that represent the table are (a), (d) and (e)

Read more about linear functions at:

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