Answer:
Step-by-step explanation
(x+3) / (2x+3) = (x +1) / (3x+2)
=> (x+3)(3x+2) = (x+1(x+3)
=> x(3x+2) + 3(3x+2) = x (2x3+) + 1(2x+3)
=> 3x2 +2 +9x+6=2x2+3x+3x +2x +3
=> 3x2+ 11x +6 = 2x2+5x +3
=>3x2+6+3=0
=>x=3x+=6
remainder would be 6
