Answer:
4.47 × 10^-21 Joules
Explanation:
We are given the frequency of the wave as 6.75 × 10^12 Hz
That is, E = hf
The plank's constant = 6.626 × 10^-34 J-s
Thus;
Energy = (6.626 × 10^-34 J-s × 6.75 × 10^12 Hz)
= 4.47 × 10^-21 Joules
Hence, the energy of the photon is 4.47 × 10^-21 Joules