The solution is:
[tex]3\leq y\leq 10[/tex]
Or
y ≥ 3 and y≤10
Further explanation:
The given inequality is compound inequality which is solved in two parts.
Given inequality is:
[tex]10 \leq 2y+4\leq 24[/tex]
The two inequalities which will be formed are:
[tex]2y+4\geq 10\\2y+4\leq 24[/tex]
Solving one by one
[tex]2y+4\geq 10\\2y+4-4\geq 10-4\\2y\geq 6\\\frac{2y}{2} \geq \frac{6}{2} \\ y \geq 3\\2y+4\leq 24\\2y+4-4\leq 24-4\\2y\leq 20\\\frac{2y}{2}\leq \frac{20}{2} \\y\leq 10[/tex]
The solution is:
[tex]3\leq y\leq 10[/tex]
Or
y ≥ 3 and y≤10
Keywords: Inequalities, Compound inequalities
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