Question

A Parking garage charges the rates in the table below. what is the rate of change.

Number of hours[1] [3] [5]

Cost of parking [10] [14] [16]

Answer 1

three divided by two

Answer 2

Answer with explanation:

We know that the rate of change in a function is given by :-

$\dfrac{\text{Change in dependent variable}}{\text{Change in independent variable}}$

Let x denotes the Number of hours and y denotes the Cost of parking .

Here , x- independent variable

y- dependent variable

Now, rate of change = $\dfrac{\text{Change in y}}{\text{Change in x}}$

$=\dfrac{14-10}{3-1}=\dfrac{4}{2}=2$

Here , the rate of change = $ 2 per hour.

Again rate of change = $\dfrac{\text{Change in y}}{\text{Change in x}}$

$=\dfrac{16-14}{5-3}=\dfrac{2}{2}=1$

Here , the rate of change = $ 1 per hour.

Since both rate of changes are not equal , it means the rate of change is not constant.