When you drop a 0.44 kg apple, Earth exerts
a force on it that accelerates it at 9.8 m/s
2
toward
the earth’s surface. According to Newton’s
third law, the apple must exert an equal
but opposite force on Earth.
If the mass of the earth 5.98 × 1024 kg, what
is the magnitude of the earth’s acceleration
toward the apple?
Answer in units of m/

Respuesta :

Answer:

7.2×10⁻²⁵ m/s²

Explanation:

F = ma

(0.44 kg) (9.8 m/s²) = (5.98×10²⁴ kg) a

a = 7.2×10⁻²⁵ m/s²

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