Answer:
A) Tan 60° [tex]\sqrt{3}[/tex] = 1.732
B) H = 12 unit
C) Area of triangle = 41.569 unit²
Step-by-step explanation:
As shown in figure, the triangle with cone angle of 60° and base value 4[tex]\sqrt{3}[/tex] unit
A) Now, Tan 60° = [tex]\sqrt{3}[/tex]
Or, Tan 60° = 1.732
B) To find value of h
since TanФ = [tex]\frac{Perpendicular}{Base}[/tex]
So, Tan 60° = [tex]\frac{h}{4\sqrt{3} }[/tex]
[tex]\sqrt{3}[/tex] = [tex]\frac{h}{4\sqrt{3} }[/tex]
∴([tex]\sqrt{3}[/tex]) × ([tex]4\sqrt{3}[/tex] = h
∴ h = 12 unit
C) Area of this triangle = [tex]\frac{1}{2}[/tex] × Perpendicular × Base
= [tex]\frac{1}{2}[/tex] × h ×[tex]4\sqrt{3}[/tex]
∵ Perpendicular h = 12 unit
So, Area = [tex]\frac{1}{2}[/tex] × 12 × [tex]4\sqrt{3}[/tex]
Hence Area of triangle = 41.569 unit²
ANSWER
