Find the solution(s) to x^2 - 12x + 36 = 0

Answer:
D
Step-by-step explanation:
plug everything into the quadratic formula:
12±√(-12²)-4(1)(36)÷2*1
12±√144-144÷2
12±√0÷2
12/2=6
6 = D
The solution to the quadratic equation x^2-12x+36=0 is x=6 only.
As the quadratic equation is given
x^2-12x+36=0
Now, we will factorize this,
For factorization, first, we have to find the factor of 36 so that adding those two numbers is -12
36= 6x6
And also (-6-6)=-12
Now, we will write the equation,
x^2-12x+36=0
x^2-6x-6x+36=0
Now, we will take the common, we get;
x(x-6)-6(x-6)=0
(x-6)(x-6)=0
x=6,6
Hence, the value of the given quadratic equation is x=6 only.
Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = ax2 + bx + c = 0 where a, b, c, ∈ R and a ≠ 0. It is the general form of a quadratic equation where 'a' is called the leading coefficient and 'c' is called the absolute term of f (x).
Examples of quadratic equations are: 6x² + 11x – 35 = 0, 2x² – 4x – 2 = 0, 2x² – 64 = 0, x² – 16 = 0, x² – 7x = 0, 2x² + 8x = 0 etc. From these examples, you can note that, some quadratic equations lack the term “c” and “bx.”
A quadratic function is one of the form f(x) = ax2 + bx + c, where a, b, and c are numbers with a not equal to zero. The graph of a quadratic function is a curve called a parabola. Parabolas may open upward or downward and vary in "width" or "steepness", but they all have the same basic "U" shape.
Learn more about quadratic equations, refer to:
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