Answer:
[tex]\large\boxed{(2^{-4})(2^{-3})}[/tex]
Step-by-step explanation:
We know:
[tex]a^{-n}=\dfrac{1}{a^n}[/tex]
Therefore
[tex]\dfrac{1}{16}=\dfrac{1}{2^4}=2^{-4}\\\\\dfrac{1}{8}=\dfrac{1}{2^3}=2^{-3}[/tex]
[tex]\dfrac{1}{16}\cdot\dfrac{1}{8}=2^{-4}\cdot2^{-3}[/tex]