Respuesta :
Answer:
k=2
Step-by-step explanation:
We are given that
Line of f(x) passes through the points (-4,0) and (0,4).
Line of g(x) pass through the points (-2,0) and (0,4).
[tex]g(x)=f(k\cdot x)[/tex]
We have to determine the value of k.
[tex]f(-4)=0[/tex]
[tex]g(-2)=0[/tex]
slope of f(x)=[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{4-0}{0+4}=1[/tex]
Equation of f(x) which is passing through the point (-4,0) with slope 1
[tex]y-0=1(x+4)[/tex]
By using slope-point form:[tex]y-y_1=m(x-x_1)[/tex]
[tex]y=x+4[/tex]
[tex]g(x)=f(kx)[/tex]
Replace x by kx
Equation of g(x)
[tex]y=kx+4[/tex]
Substitute x=-2
[tex]g(-2)=-2k+4[/tex]
[tex]-2k+4=0[/tex]
[tex]2k=4[/tex]
[tex]k=\frac{4}{2}=2[/tex]
Hence, the value of [tex]k=2[/tex]