Answer:
The lines are parallel
The graph in the attached figure
Step-by-step explanation:
we have
[tex]3x=4y-5[/tex] ---> equation A
[tex]\frac{2}{3}y=\frac{x}{2}+8[/tex] -----> equation B
we know that
If two lines are parallel, then their slopes are the same
If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)
step 1
Find the slope of the line A
[tex]3x=4y-5[/tex]
Isolate the variable y
Adds 5 both sides
[tex]4y=3x+5[/tex]
Divide by 4 both sides
[tex]y=\frac{3}{4}x+\frac{5}{4}[/tex]
The slope is
[tex]m_A=\frac{3}{4}[/tex]
step 2
Find the slope of line B
[tex]\frac{2}{3}y=\frac{x}{2}+8[/tex]
Multiply by 6 both sides to remove the fractions
[tex]4y=3x+48[/tex]
Divide by 4 both sides
[tex]y=\frac{3}{4}x+\frac{48}{4}[/tex]
Simplify
[tex]y=\frac{3}{4}x+12[/tex]
The slope is
[tex]m_B=\frac{3}{4}[/tex]
step 3
Compare the slopes
we have
[tex]m_A=\frac{3}{4}[/tex]
[tex]m_B=\frac{3}{4}[/tex]
so
[tex]m_A=m_B[/tex]
therefore
The lines are parallel
see the attached figure to better understand the problem