Respuesta :

Answer:

(- 3, 0) and (- 1, 0)

Step-by-step explanation:

Given

x² + 4x + 3 = 0 ← in standard form

(x + 1)x + 3) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

x + 3 = 0 ⇒ x = - 3

coordinates of the roots are (- 3, 0) and (- 1, 0)

Solving the quadratic equation, the coordinates of the roots are: (-1,0) and (-3,0)

The quadratic equation given is:

[tex]x^2 + 4x + 3[/tex]

Which has coefficients [tex]a = 1, b = 4, c = 3[/tex].

Now, we find the solutions:

[tex]\Delta = 4^2 - 4(1)(3) = 4[/tex]

[tex]x_{1} = \frac{-4 + \sqrt{4}}{2} = -1[/tex]

[tex]x_{2} = \frac{-4 - \sqrt{4}}{2} = -3[/tex]  

The coordinates of the roots are [tex](x_1, 0)[/tex] and [tex](x_2, 0)[/tex], as a root is a value of x when y = 0, thus, in the problem, (-1,0) and (-3,0).

A similar problem is given at https://brainly.com/question/13729358

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