Respuesta :
Answer:
(- 3, 0) and (- 1, 0)
Step-by-step explanation:
Given
x² + 4x + 3 = 0 ← in standard form
(x + 1)x + 3) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 1 = 0 ⇒ x = - 1
x + 3 = 0 ⇒ x = - 3
coordinates of the roots are (- 3, 0) and (- 1, 0)
Solving the quadratic equation, the coordinates of the roots are: (-1,0) and (-3,0)
The quadratic equation given is:
[tex]x^2 + 4x + 3[/tex]
Which has coefficients [tex]a = 1, b = 4, c = 3[/tex].
Now, we find the solutions:
[tex]\Delta = 4^2 - 4(1)(3) = 4[/tex]
[tex]x_{1} = \frac{-4 + \sqrt{4}}{2} = -1[/tex]
[tex]x_{2} = \frac{-4 - \sqrt{4}}{2} = -3[/tex]
The coordinates of the roots are [tex](x_1, 0)[/tex] and [tex](x_2, 0)[/tex], as a root is a value of x when y = 0, thus, in the problem, (-1,0) and (-3,0).
A similar problem is given at https://brainly.com/question/13729358