Question

Given the equation square root of quantity 3x minus 2 end quantity equals 4, solve for x and identify if it is an extraneous solution.

Answer 1

Answer:

Step-by-step explanation:

This is your equation:

$\sqrt{3x-2}=4$

To undo that square root, square both sides, giving you:

3x - 2 = 16.  Solving for x gives us

3x = 18 so

x = 6

If you plug 6 back into the equation, the original one, you get that the square root of 16 = 4, which is true.