Use the graph representing bacteria decay to estimate the domain of the function and solve for the average rate of change across the domain.

The domain of a function is the set of values of the independent variable for which a function is defined. The domain is located along the x-axis where the graph is defined from the starting point to the endpoint.
From the graph, we can see that:
Also from the graph, we can observe that the values of x start from x = 0 to x = 18.
Thus the domain of the function is [tex]\boxed{ \ [0, 18] \ or \ 0 \leq x \leq 18 \ }[/tex]
The formula for the average rate of change on a given interval [tex][a, b][/tex] is as follows:
[tex]\boxed{ \ \frac{\Delta y}{\Delta x} = \frac{f(b) - f(a)}{b - a} \ }[/tex]
Because the domain of the function is [0, 18], we prepare:
And now, let us solve for the average rate of change across the domain.
[tex]\boxed{ \ \frac{\Delta y}{\Delta x} = \frac{0 - 60}{18 - 0} \ }[/tex]
[tex]\boxed{ \ \frac{\Delta y}{\Delta x} = \frac{- 60}{18} \ }[/tex]
[tex]\boxed{\boxed{ \ \frac{\Delta y}{\Delta x} = -3.33 \ }}[/tex]
Note that the y-values change down 3.33 units in thousands every time the x-values change 1 unit in minutes, at intervals of the domain.
We conclude that from t = 0 to t = 18 (in minutes), every 1 minute as many as 3.33 thousand bacteria decay.
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The domain of a function is the set of input values of the function.
From the graph, we have the following highlights.
So, the domain of the function is: [0,18]
The average rate of change is calculated as:
[tex]\mathbf{m = \frac{f(b) - f(a)}{b - a}}[/tex]
From the graph, we have:
[tex]\mathbf{f(0) = 60}[/tex]
[tex]\mathbf{f(18) = 0}[/tex]
So, we have:
[tex]\mathbf{m = \frac{f(18) - f(0)}{18 - 0}}[/tex]
This gives
[tex]\mathbf{m = \frac{0 - 60}{18}}[/tex]
[tex]\mathbf{m = -\frac{ 60}{18}}[/tex]
[tex]\mathbf{m = -3.33}[/tex]
Hence, the average rate of change across the domain is -3.33
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