Question

What is the coefficient of x in the division (18x^3+12x^2-3x)/6x^2?

A.
3

B.
2

C.
-0.5

D.
-3

Answer 1

That would be A.... when you divide the trinomial in bracket by the $6x^{2}$ you will realize that the coefficient of the x is 3.  If you want me to send a picture of the division please indicate.

Answer 2

Answer:

3

Step-by-step explanation:

Given : $\frac{18x^3+12x^2-3x}{6x^2}$

To Find: What is the coefficient of x in the division

Solution:

$\frac{18x^3+12x^2-3x}{6x^2}$

On Dividing we

Quotient = 3x+2

Remainder = -3x

So, coefficient of x in quotient = 3

Thus the coefficient of x in the division $\frac{18x^3+12x^2-3x}{6x^2}$ is 3

Hence Option A is correct