Question

Differentiate the equation in the picture.

S(2)=1

Answer 1

Answer:

y(t)''=3y(t)^2-(s2+13)

Step-by-step explanation:d[y(t)]/dt is the same thing as y'(t). Thus:

d[y'(t)]=y''(t); d[y(t)^3]=3.y(t)^(3-1)=3y(t)^2;  and d[k.y(t)] is k, where k is a variable or constant that independs on y.