Question

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the
correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag
the item to the trashcan. Click the trashcan to clear all your answers.
Enter the equation of the circle described below.
Center (3,-2), radius = 5

Answer 1

Equation of circle is:

$x^2+y^2-6x+4y - 12 = 0$

Further explanation:

We have to use the standard form of equation of a circle to find the equation of circle from given details

The general equation of circle is:

$(x-h)^2+(y-k)^2=r^2$

Given

Centre = (h,k) = (3, -2)

Radius = r = 5

Putting the values in the general equation

$(x-3)^2+(y-(-2))^2 = (5)^2\\(x-3)^2+(y+2)^2 = 25\\(x^2-6x+9)+(y^2+4y+4) = 25\\x^2+y^2-6x+4y+9+4-25 = 0\\x^2+y^2-6x+4y - 12 = 0$

Keywords: Circles, Equation of circle

Learn more about circles at:

• brainly.com/question/13063819
• brainly.com/question/8618791

#LearnwithBrainly

Answer 2

Answer:

I know I may be a year or two late to this question but the answer is:

$(x-3)^{2} +(y+2)^{2} =25$.

Step-by-step explanation:

The general equation of a circle is:

$(x-h)^{2} +(y-k)^{2} =r^{2}$, where $Center = (h, k)$, and $Radius = r$.

Insert the center and radius of the circle:

$(x-3)^{2} +(y-(-2))^{2} =5^{2}$.

Therefore, the equation of the circle is $(x-3)^{2} +(y+2)^{2} =25$.