The expression which correctly sets up the quadratic formula to solve the equation is Option (A) [tex]\frac{-(-4) +- \sqrt{(-4)^{2} - 4(1)(3) } }{2(1)}[/tex]
Theory of quadratic equation -
A quadratic equation is defined as any equation containing one term in which the unknown is squared and no term in which it is raised to a higher power.
Example of quadratic equation in x is - [tex]4x^{2} + 4 = 9x[/tex]
How to solve any quadratic equation using Sridharacharya formula ?
Let us represent a general quadratic equation in x , [tex]ax^{2} + bx + c = 0[/tex] where a, b and c are coefficients of the terms.
According to Sridharacharya formula , the value of x or the roots of the quadratic equation is -
x = [tex]\frac{-b +- \sqrt{(b)^{2} - 4(a)(c) } }{2(a)}[/tex]
The given equation is [tex]x^{2} - 4x + 3 = 0[/tex]
Comparing with the general equation of quadratic equation , we get a = 1, b = -4 , c = 3.
Putting the values of coefficients in the Sridharacharya formula ,
x = [tex]\frac{-(-4) +- \sqrt{(-4)^{2} - 4(1)(3) } }{2(1)}[/tex] which gives Option (A).
To learn more about Sridharacharya formula , refer -
https://brainly.com/question/2216042
#SPJ2
