Answer:
[tex]y=3x-3[/tex]
Step-by-step explanation:
The equation of the line with the slope [tex]m[/tex] and passing through the point [tex](x_0,y_0)[/tex] is
[tex]y-y_0=m(x-x_0)[/tex]
In your case,
[tex]m=3\\ \\x_0=3\\ \\y_0=6[/tex]
Hence, the equation of the line is
[tex]y-6=3(x-3)\\ \\y-6=3x-9\\ \\y=3x-9+6\\ \\y=3x-3[/tex]