Question

A person shoots a rapid-fire stream of 2.8 g bullets at an indestructible target at a rate of 92 bullets per minute. The speed of each bullet is 474 m/s. Upon hitting the target, the bullets simply stop and just fall to the ground (i.e., the final momentum of each bullet is 0). What is the magnitude of the average force on the target?

Answer 1

Answer:

F = 2N

Explanation:

Impulse p is given by:

$\overrightarrow p = m \overrightarrow v$

The average forces F is given by:

$\overrightarrow F=\frac{\overrightarrow{\delta p}}{\delta t}$

Combining both equations:

$F=\frac{\delta (m\cdot\overrightarrow v)}{\delta t}$