Answer:
The Sled goes fast at 25.60 m/s
Explanation:
According to fundamentals, velocity of any body is equal to the product of its acceleration and time period that is,
velocity = acceleration x time ;
According to question a sled starts from rest and slides down a [tex]38.0^{\circ}[/tex] hill and the time taken to happen so is 4.24s
we have, acceleration =[tex]\mathrm{g} \sin \theta[/tex]
therefore acceleration = 9.81[tex]\sin 38^{\circ}[/tex]
= 6.039 [tex]\frac{m}{s^{2}}[/tex] for the case under consideration;
hence the velocity may be obtained as v=6.039x4.24 = 25.60 m/s
