Question

Determine the mass in grams of 3.00 × 10²¹ atoms of arsenic. (The mass of one mole of arsenic is 74.92 g.)

Answer 1

Answer:

The answer to your question is: 0.373 g

Explanation:

Data

mass = ? g

atoms = 3 x 10 ²¹

AM = 74.92 g

Process

                     1 mol of As ------------------  6.023 x 10²³ atoms

                     x                  ------------------  3 x 10 ²¹  atoms

                     x = 4.98 x 10⁻³ moles

                     1 mol ------------------------   74.92 g

                     4.98 x 10⁻³ moles-------     x

                     x = (4.98 x 10⁻³ x 74.92)/1

                     x = 0.373 g of As

Answer 2

The number of atoms present in a mole of elements can be given by the Avagadro number. The value of the Avagadro number has been equal to $\rm 6.023\;\times\;10^2^3$ .

1 mole = $\rm 6.023\;\times\;10^2^3$ atoms

The mass of 1 mole of As is 74.92 grams.

1 mole = 74.92 grams

$\rm 6.023\;\times\;10^2^3$ atoms = 74.92 grams.

The number of atoms of As has been = $\rm 3.0\;\times\;10^2^1$ atoms.

$\rm 6.023\;\times\;10^2^3$ atoms = 74.92 grams.

$\rm 3.0\;\times\;10^2^1$ atoms = $\rm \dfrac{74.92}{\rm 6.023\;\times\;10^2^3}\;\times\;3.00\;\times\;10^2^1$ grams

$\rm 3.0\;\times\;10^2^1$ atoms = 3.73 grams.

The mass of $\rm 3.0\;\times\;10^2^1$ atoms of Arsenic has been 3.73 grams.

For more information about the mass of atoms, refer to the link:

https://brainly.com/question/10312269