If 2-3√x =8 , What is the value of x? Please help me in solving this problem, tell me in detail,

The correct answer is option C: 4
Further explanation:
Given equation is a radical equation. In order to solve radical equations, the term with radical is squared to exclude the square root.
Given
[tex]2-3\sqrt{x} =8[/tex]
Using subtraction property for equality
[tex]-2+2-3\sqrt{x} =8-2\\-3\sqrt{x} =6[/tex]
Dividing both sides by -3
[tex]\frac{-3\sqrt{x} }{-3} = \frac{6}{-3}\\\sqrt{x} =-2[/tex]
Taking square on both sides
[tex](\sqrt{x} )^2 = (-2)^2\\x = 4[/tex]
Hence the correct answer is: C. 4
Keywords: Radical equations, square root
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