Answer:
[tex]\large\boxed{\dfrac{26}{35}}[/tex]
Step-by-step explanation:
[tex]2\dfrac{1}{7}-1\dfrac{2}{5}\\\\\text{Find LCD}=7\cdot5=35\\\\2\dfrac{1}{7}=2\dfrac{1\cdot5}{7\cdot5}=2\dfrac{5}{35}\\\\1\dfrac{2}{5}=1\dfrac{2\cdot7}{5\cdot7}=1\dfrac{14}{35}\\\\\\2\dfrac{1}{7}-1\dfrac{2}{5}=2\dfrac{5}{35}-1\dfrac{14}{35}=1\dfrac{35+5}{35}-1\dfrac{14}{35}=1\dfrac{40}{35}-1\dfrac{14}{35}=\dfrac{40-14}{35}=\dfrac{26}{35}[/tex]
