Respuesta :

Answer:

System with earth at centre and body revolving around it.

Explanation:

Given that gravitational and kinetic energy should be nearly equal without changing the mass or height.

So ,

Let us consider a system where we have a body revolving around the earth with a velocity such that it remains in orbit.

Gravitational potential energy at a height h from the ground is given by

[tex]-\frac{GMm}{R+h}[/tex]

[tex]\frac{1}{2} mv^{2}=\frac{GMm}{R+h}[/tex]

For velocities satisfying abow the system can have gpe and ke same in ideal cases.

[Note: For the abow velocity usually the body will escape as potential at infinity will be zero .This can just be a type of system where gpe and ke will be equal without mass and height changing.]

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