Answer:
System with earth at centre and body revolving around it.
Explanation:
Given that gravitational and kinetic energy should be nearly equal without changing the mass or height.
So ,
Let us consider a system where we have a body revolving around the earth with a velocity such that it remains in orbit.
Gravitational potential energy at a height h from the ground is given by
[tex]-\frac{GMm}{R+h}[/tex]
[tex]\frac{1}{2} mv^{2}=\frac{GMm}{R+h}[/tex]
For velocities satisfying abow the system can have gpe and ke same in ideal cases.
[Note: For the abow velocity usually the body will escape as potential at infinity will be zero .This can just be a type of system where gpe and ke will be equal without mass and height changing.]