Answer:
There will be No change in volume.
Explanation:
Ideal Gas Equation is used to solve this :
PV=nRT;
P is pressure in Pa,
V is volume in [tex]m^3[/tex],
n is number of moles of gas;
R is the universal gas constant, 8.31 J/K mol
T is temperature in Kelvin
when mass is said to be fixed, the number of moles will also be fixed, too. So combining both the constant term n and R which gives
PV=kT
where k is constant.
V= [tex]\frac{k T}{P}[/tex]
So the equation represents that, Volume V will remains unchanged when pressure and temperature are both doubled, therefore the numerator term T and the denominator term P are both gets affected by multiplication of 2, hence by cancellations:
V = [tex]\mathrm{k} \frac{T \times 2}{P \times 2}[/tex]= [tex]\frac{k T}{P}[/tex]
