Respuesta :
Answer(there are assumptions for this answer that you need to confirm and look at):
Assumptions: [tex]u(x)=x^2+3[/tex] and [tex]w(x)=\sqrt{x+2}[/tex]
Answer if the operation is multiplication:
If you meant a closed dot which is the symbol for multiplication.
[tex](u \cdot w)(2)=14[/tex]
[tex](w \cdot u)(2)=14[/tex]
Answer if the operation is composition:
If you meant an open dot which is the symbol for composition.
[tex](u \circ w)(2)=7[/tex]
[tex](w \circ u)(2)=3[/tex]
Note: I don't know if you actually meant [tex]w(x)=\sqrt{x+2}[/tex] or if [tex]w(x)=\sqrt{x}+2[/tex]. Please let me know one way or the other.
Step-by-step explanation:
If we assume the functions are:
[tex]u(x)=x^2+3[/tex]
[tex]w(x)=\sqrt{x+2}[/tex]
[tex]u \cdot w=w \cdot u[/tex] since multiplication is commutative.
[tex]u(2)=2^2+3[/tex]
[tex]u(2)=4+3[/tex]
[tex]u(2)=7[/tex]
[tex]w(2)=\sqrt{2+2}[/tex]
[tex]w(2)=\sqrt{4}[/tex]
[tex]w(2)=2[/tex]
We are asked to find [tex](u \cdot w)(2)[/tex] and [tex](w \cdot u)(2)[/tex].
The order doesn't matter in multiplication.
[tex](u \cdot w)(2)[/tex]
[tex]u(2) \cdot w(2)[/tex]
[tex]7 \cdot 2[/tex]
[tex]14[/tex]
[tex](w \cdot u)(2)[/tex]
[tex]w(2) \cdot u(2)[/tex]
[tex]2 \cdot 7[/tex]
[tex]14[/tex]
Now you might have meant composition which symbolized with an open circle, not a closed one.
[tex](u \circ w)(2)[/tex]
[tex]u(w(2))[/tex]
[tex]u(2)[/tex] since [tex]w(2)=2[/tex]
[tex]2^2+3[/tex]
[tex]4+3[/tex]
[tex]7[/tex]
[tex](w \circ u)(2)[/tex]
[tex]w(u(2))[/tex]
[tex]w(7)[/tex] since [tex]u(2)=7[/tex]
[tex]\sqrt{7+2}[/tex]
[tex]\sqrt{9}[/tex]
[tex]3[/tex]