Question

Calculate the molar solubility of AgCl, using its Ksp value of 1.8 x 10-10.

Answer 1

Answer:1.34 ×10^-5

Explanation:

AgCl = (Ag+) (Cl-)

=(S)(S)

= S²

S stands for molar solubility

Ksp =S² = 1.80 × 10^ -10

S= √[1.80 × 10^ -10]

=1.34 × 10^-5