Respuesta :
Answer:
[tex]A=50\ units^2[/tex]
Step-by-step explanation:
we know that
The area of rectangle is equal to
[tex]A=LW[/tex]
The coordinates of vertices are
[tex]A(-5,5),B(-1,7),C(4,-3),D(0,-5)[/tex]
using a graphing tool
Plot the coordinates of rectangle to better understand the problem
see the attached figure
the formula to calculate the distance between two points is equal to
[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]
we have that
[tex]L=AD,W=AB[/tex]
Find out the distance AD
we have
[tex]A(-5,5),D(0,-5)[/tex]
substitute in the formula
[tex]L=\sqrt{(-5-5)^{2}+(0+5)^{2}}[/tex]
[tex]L=\sqrt{(-10)^{2}+(5)^{2}}[/tex]
[tex]L=\sqrt{125}\ units[/tex]
Find out the distance AB
we have
[tex]A(-5,5),B(-1,7)[/tex]
substitute in the formula
[tex]W=\sqrt{(7-5)^{2}+(-1+5)^{2}}[/tex]
[tex]W=\sqrt{(2)^{2}+(4)^{2}}[/tex]
[tex]W=\sqrt{20}\ units[/tex]
The area of rectangle is equal to
[tex]A=(\sqrt{125})(\sqrt{20})[/tex]
[tex]A=50\ units^2[/tex]
