Answer:
[tex]3400[/tex] Hz
Explanation:
We know that
1 cm = 0.01 m
[tex]L[/tex] = Length of the human ear canal = 2.5 cm = 0.025 m
[tex]V[/tex] = Speed of sound = 340 ms⁻¹
[tex]f[/tex] = First resonant frequency
The human ear canal behaves as a closed pipe and for a closed pipe, nth resonant frequency is given as
[tex]f = \frac{(2n - 1)V}{4L}[/tex]
for first resonant frequency, we have n = 1
Inserting the values
[tex]f = \frac{(2(1) - 1) 340}{4(0.025)}[/tex]
[tex]f = \frac{340}{4(0.025)}[/tex]
[tex]f = 3400[/tex] Hz